## Wednesday, December 9, 2015

### EJSS Dice Throw Model

EJSS Dice Throw Model

## Theory

Assume the number of radioactive nucleus is N(t) --- not yet decayed into daughter product.
Each nucleus has the same probability p (p<1) decayed into daughter product.
It means that dN(t)/dt= -p*N(t) , where dN(t) is the number of nucleus decayed into daughter product at time t.
The solution is N(t)=N0 e -pt = N0 e -(ln2/T0.5)) t where N(0) is total number of nucleus at time t.
Each box represent a nucleus.
This applet let you set the probability for a nucleus to decay and watch how the number of decayed nuclei (color changed to RED)  increased with time t.

## Other Resources

2. http://www.phy.ntnu.edu.tw/ntnujava/index.php?topic=194.0 by Fu-Kwun Hwang original Java version
3. http://www.opensourcephysics.org/items/detail.cfm?ID=10576 by Wolfgang Christian similar Java version
 end state of dice =1, stop rolling, else keep rolling http://iwant2study.org/ospsg/index.php/interactive-resources/physics/06-quantum-physics/02-nuclear/317-decaychangenweedice

 end state of dice =1 and 2, stop rolling, else keep rolling http://iwant2study.org/ospsg/index.php/interactive-resources/physics/06-quantum-physics/02-nuclear/317-decaychangenweedice

 end state of dice =1,2,3, stop rolling, else keep rolling http://iwant2study.org/ospsg/index.php/interactive-resources/physics/06-quantum-physics/02-nuclear/317-decaychangenweedice

 end state of dice =1,2,3,4 stop rolling, else keep rolling http://iwant2study.org/ospsg/index.php/interactive-resources/physics/06-quantum-physics/02-nuclear/317-decaychangenweedice

 end state of dice =1,2,3,4,5 stop rolling, else keep rolling http://iwant2study.org/ospsg/index.php/interactive-resources/physics/06-quantum-physics/02-nuclear/317-decaychangenweedice

 For N0 =1024 dice, end state of dice =1, stop rolling, else keep rollinghttp://iwant2study.org/ospsg/index.php/interactive-resources/physics/06-quantum-physics/02-nuclear/317-decaychangenweedice