customized from https://www.geogebratube.org/material/show/id/37863 by damienchew
http://tube.geogebra.org/student/m359109
students must be able to understand why $ \angle $ at Centre = 2 times $ \angle $ at Circumference.
Steps:
- Compare angles at the centre of a circle with angle touching the circumference.
- vary the $ \angle $ at Centre O for which it is acute less than 90 °

example of acute angle at centre O, what is the value of $ \angle $ at Circumference point A? - write down the value of $ \angle $ at Centre O and $ \angle $ at Circumference point A
- vary the $ \angle $ at Centre O for which it is obtuse more than 90° and less than 180°.

example of obtuse angle at centre O, what is the value of $ \angle $ at Circumference point A? - do step 3
- vary the $ \angle $ at Centre O for which it is reflex more than 180°.
- do step 3
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| example of reflex angle at centre O, what is the value of $ \angle $ at Circumference point A? |
Thinking:
looking at the evidence of the table of recorded values, suggest a relationship between
$ \angle $ at Centre O and $ \angle $ at Circumference point A.Conclusion:
$ \angle $ at Centre = 2 times $ \angle $ at Circumference.
Proof:
Let $ \angle $AOC = 2a
Let $ \angle $BOC = 2b
Then $ \angle $AOB = 360° - 2a – 2b
$ \angle $ OCA = 90° – a (isosceles triangle)
$ \angle $BCO = 90° – b (isosceles triangle)
Therefore, $ \angle $ACB = (90° – a) + (90° – b) = 180° – a – b
Hence, $ \angle $AOB = 2$ \angle $ACB ($ \angle $ at Centre = 2 times $ \angle $ at Circumference) Proven

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