Theory
the equation for the drag force on the square paper is may be assumed to be is the form of $ F = \frac{1}{2} \rho v^{2} C_{D} A $
where F is the aerodynamic drag force
$ \rho $ is the is the density of the fluid
$ v $ is the speed of the object relative to the fluid
$ A $ is the cross sectional area
$ C_{D} $ is the drag coefficient – a dimensionless number.
Area, A/cm2
|
289
|
249
|
190
|
169
|
130
|
88
|
Terminal Velocity, v/ cm s-1
|
1.66
|
1.70
|
2.02
|
2.12
|
2.31
|
2.66
|
cross sectional area A = 88 cm^2, Terminal velocity vT = 2.66 cm/s |
cross sectional area A = 130 cm^2, Terminal velocity vT = 2.31 cm/s |
cross sectional area A = 169 cm^2, Terminal velocity vT = 2.12 cm/s |
cross sectional area A = 190 cm^2, Terminal velocity vT = 2.02 cm/s |
cross sectional area A = 249 cm^2, Terminal velocity vT = 1.70 cm/s |
cross sectional area A = 289 cm^2, Terminal velocity vT = 1.66 cm/s |
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